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## Henry Bushby Transcription pages

### VM533B94v4-p045.jpg

Revision as of May 29, 2014, 10:11:07 AM created by DPepper |
Revision as of May 29, 2014, 10:13:06 AM edited by DPepper |
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− | 45<br>an r.k.without obliterating<br>2c.<br>Of course this plait could be <br>obtained directly from S<sub>3</sub> <sup>4b</sup>/<sub>8c</sub> thus :-<br>Here on a 1z k. 2 adjacent bights<br>have been cut & the alternate parts<br>x & 2, 1 & 3, joined without alternate<br>crossings, producing an i.k. of<br>c – 1 crossings = 7 on 1z.<br>Therefore among knots of 7c are<br>S<sub>2 </sub> <sup> | + | 45<br>an r.k.without obliterating<br>2c.<br>Of course this plait could be <br>obtained directly from S<sub>3</sub> <sup>4b</sup>/<sub>8c</sub> thus :-<br>Here on a 1z k. 2 adjacent bights<br>have been cut & the alternate parts<br>x & 2, 1 & 3, joined without alternate<br>crossings, producing an i.k. of<br>c – 1 crossings = 7 on 1z.<br>Therefore among knots of 7c are<br>S<sub>2 </sub> <sup>7b</sup>/<sub>7c</sub>, the T.H; & this i.k. plait.<br>Presumably every 1z. k in S<sub>3</sub><br>could be similarly made to produce<br>an i.k. on 1z. with 1c. less than<br>the number. (S<sub>3</sub> <sup>5b</sup>/<sub>10c</sub> & S<sub>3</sub> <sup>7b</sup>/<sub>14c</sub> can.)<br> |

## Revision as of May 29, 2014, 10:13:06 AM

45

an r.k.without obliterating

2c.

Of course this plait could be

obtained directly from S_{3} ^{4b}/_{8c} thus :-

Here on a 1z k. 2 adjacent bights

have been cut & the alternate parts

x & 2, 1 & 3, joined without alternate

crossings, producing an i.k. of

c – 1 crossings = 7 on 1z.

Therefore among knots of 7c are

S_{2 } ^{7b}/_{7c}, the T.H; & this i.k. plait.

Presumably every 1z. k in S_{3}

could be similarly made to produce

an i.k. on 1z. with 1c. less than

the number. (S_{3} ^{5b}/_{10c} & S_{3} ^{7b}/_{14c} can.)