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# Scripto | Revision Difference | Transcription

## Henry Bushby Transcription pages

### VM533B94v4-p262.jpg

Revision as of May 29, 2014, 6:11:34 AM
edited by JLee
Revision as of May 29, 2014, 6:14:40 AM
edited by JLee
Line 13: Line 13:

y even: y-2[over]2 + y- <s>2</s>4[over]2 + y-2[over]2 = 3y-8[over]2.<br>

y even: y-2[over]2 + y- <s>2</s>4[over]2 + y-2[over]2 = 3y-8[over]2.<br>

<u> For example</u>: Required [liks?] with 6c.<br>

<u> For example</u>: Required [liks?] with 6c.<br>
<u>B.</u> (i) 6-2=4, 6-2=5.<br>
+
<u>B.</u> (i) 6-2=4, 6-1=5.<br>

With 4 join 1 ^<i>[Oro?]</i> to all even nos. up to<br>

With 4 join 1 ^<i>[Oro?]</i> to all even nos. up to<br>

4, [rig?] 2,4. This gives 6-2[over]2=2. They are<br>

4, [rig?] 2,4. This gives 6-2[over]2=2. They are<br>

## Revision as of May 29, 2014, 6:14:40 AM

263
I2 only
(ii) Then with r.k (y-1) join 1 to all odd
Nos. ^"[Fro?]" to y-1 except 5.as in A-i. This gives y-c4[over]2 knots.
(iii) with r.k.y, join 1 to all even
nos ^"not" up to & including y +1., but ^excluding 2& com-
mencing with 1[symbol]4. This will give
y-2[over]2 knots different from B.i.
The totals thus obtained therefore
are:-
y odd: y-3+y-2[over]2 = 2y-4[over]2 = y-2
y-3+y-3+y-3[over]2 = 3(y-3)[over]2
y even: y-2[over]2 + y- 24[over]2 + y-2[over]2 = 3y-8[over]2.
For example: Required [liks?] with 6c.
B. (i) 6-2=4, 6-1=5.
With 4 join 1 ^[Oro?] to all even nos. up to
4, [rig?] 2,4. This gives 6-2[over]2=2. They are
the Weaver & Endless chain.
(ii) With 5 join 1 ^[Fro?] to odd nos. up to 5, [rig?]</>,
<s>3, 5.
excluding 5. This gives [rig?] 3. This gives
6-4[over]2 = 1. It is the Timber Hitch.
(iii) With r.k.6 join 1, ^not to even nos.
up to 6, excluding 2. [rig?] 4,6. This gives
46-2[over]2 = 2. They are Ended Chain & 1z Granny.
Total 6-2+6-4+6-2[over]2 = 18-8[over]2 = 5.
[Vertical diagram and caption in a square box:] 6c i 6 2z. not get found. = I[subscript]4 2[over]6 reversed.] [Vertical text outside the square box:] Also Reef, "A", p179.