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## Henry Bushby Transcription pages

### VM533B94v4-p262.jpg

Revision as of May 29, 2014, 6:32:03 AM edited by JLee |
Revision as of May 29, 2014, 6:55:01 AM edited by JLee |
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− | + | I2 Only<br> | |

+ | 95) odd c gives c-1 [superscript:]c-1[over]2 of (c+1)[subscript:] c-1[over]2 of 9c+2)}<u>[Oro?]</u><br> | ||

+ | odd c give <s>same</s> ^<c-1 knots</i> for <u>not.</u><br> | ||

+ | But some will be repetitions.<br> | ||

+ | 96) Required: knots with y.c. Proceed<br> | ||

+ | as follows:-<br> | ||

+ | <u>A.</u> Suppose y is odd.<br> | ||

+ | 9i0 <u>[Oro?]</u>: - y c can be derived from<br> | ||

+ | r.k. y-2, & r.k y-1.<br> | ||

+ | (iii) With r.k.(2-2) join 1 to all even nos.<br> | ||

+ | "<u>[Oro?]</u>" up to & including 1[symbol] y-2. This will give<br> | ||

+ | y-3[over]2 knots of y crossings.<br> | ||

+ | Then with r.k (y-10 join 1 ^<i><u>[Oro?]</u></i> to all odd<br> | ||

+ | nos. ^<i>except 5</i> up to & including 1[symbol]y. This will <br> | ||

+ | give <s>y-3[over]2 of y crossings.</s> <s><u>y-3</u></s> 4-3[over]2 knots. <br> | ||

+ | (iii) <s> As y is odd these are no fresh knots</s> ^<i> with. r.k. y join 1 <u>not </u> |

## Revision as of May 29, 2014, 6:55:01 AM

I2 Only

95) odd c gives c-1 [superscript:]c-1[over]2 of (c+1)[subscript:] c-1[over]2 of 9c+2)}__[Oro?]__

odd c give ~~same~~ ^<c-1 knots</i> for __not.__

But some will be repetitions.

96) Required: knots with y.c. Proceed

as follows:-

__A.__ Suppose y is odd.

9i0 __[Oro?]__: - y c can be derived from

r.k. y-2, & r.k y-1.

(iii) With r.k.(2-2) join 1 to all even nos.

"__[Oro?]__" up to & including 1[symbol] y-2. This will give

y-3[over]2 knots of y crossings.

Then with r.k (y-10 join 1 ^* [Oro?]* to all odd

nos. ^

*except 5*up to & including 1[symbol]y. This will

give

__y-3__

(iii)

*with. r.k. y join 1*

__not__