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## Henry Bushby Transcription pages

### VM533B94v4-p262.jpg

Revision as of May 29, 2014, 6:55:01 AM edited by JLee |
Revision as of Jun 2, 2014, 5:53:20 AM edited by JLee |
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− | + | I<sub>2</sub> Only<br> | |

− | 95) odd c gives c-1 | + | 95) odd c gives c-1 <sup>c-1</sup>/<sub>2</sub> of (c+1)<br><sup>c-1</sup>/<sub>2</sup> of (c+2)}[bracket with line above]<u>[Oro?]</u><br> |

− | odd c give <s>same</s> ^<c-1 knots</i> for | + | odd c give <s>same</s> ^<i>c-1 knots</i> for <u>not.</u><br> |

But some will be repetitions.<br> | But some will be repetitions.<br> | ||

− | + | (6) Required: knots with y.c. Proceed<br> | |

as follows:-<br> | as follows:-<br> | ||

<u>A.</u> Suppose y is odd.<br> | <u>A.</u> Suppose y is odd.<br> | ||

− | + | (i)<u>[Oro?]</u>: - y c can be derived from<br> | |

r.k. y-2, & r.k y-1.<br> | r.k. y-2, & r.k y-1.<br> | ||

(iii) With r.k.(2-2) join 1 to all even nos.<br> | (iii) With r.k.(2-2) join 1 to all even nos.<br> |

## Revision as of Jun 2, 2014, 5:53:20 AM

I_{2} Only

95) odd c gives c-1 ^{c-1}/_{2} of (c+1)^{c-1}/_{2</sup> of (c+2)}[bracket with line above][Oro?]
odd c give same ^c-1 knots for not.
But some will be repetitions.
(6) Required: knots with y.c. Proceed
as follows:-
A. Suppose y is odd.
(i)[Oro?]: - y c can be derived from
r.k. y-2, & r.k y-1.
(iii) With r.k.(2-2) join 1 to all even nos.
"[Oro?]" up to & including 1[symbol] y-2. This will give
y-3[over]2 knots of y crossings.
Then with r.k (y-10 join 1 ^[Oro?] to all odd
nos. ^except 5 up to & including 1[symbol]y. This will
give y-3[over]2 of y crossings. y-3 4-3[over]2 knots.
(iii) As y is odd these are no fresh knots ^ with. r.k. y join 1 not
}