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# Scripto | Revision Difference | Transcription

## Henry Bushby Transcription pages

### VM533B94v4-p262.jpg

Revision as of Jun 2, 2014, 5:57:22 AM
edited by JLee
Revision as of Jun 2, 2014, 5:57:54 AM
edited by JLee
Line 8: Line 8:

(i)<u>[Oro?]</u>: - y c can be derived from<br>

(i)<u>[Oro?]</u>: - y c can be derived from<br>

r.k. y-2, & r.k y-1.<br>

r.k. y-2, & r.k y-1.<br>
(iii) With r.k.(y-2) join 1 to all even nos.<br>
+
(ii) With r.k.(y-2) join 1 to all even nos.<br>

"<u>[Oro?]</u>" up to & including 1[symbol] y-2. This will give<br>

"<u>[Oro?]</u>" up to & including 1[symbol] y-2. This will give<br>

y-3[over]2 knots of y crossings.<br>

y-3[over]2 knots of y crossings.<br>

## Revision as of Jun 2, 2014, 5:57:54 AM

I2 Only
(5) odd c gives c-1 knots c-1/2 of (c+1)
c-1/2 of (c+2)}[bracket with line above][Oro?]
odd c give same ^c-1 knots for not.
But some will be repetitions.
(6) Required: knots with y.c. Proceed
as follows:-
A. Suppose y is odd.
(i)[Oro?]: - y c can be derived from
r.k. y-2, & r.k y-1.
(ii) With r.k.(y-2) join 1 to all even nos.
"[Oro?]" up to & including 1[symbol] y-2. This will give
y-3[over]2 knots of y crossings.
Then with r.k (y-10 join 1 ^[Oro?] to all odd
nos. ^except 5 up to & including 1[symbol]y. This will
give y-3[over]2 of y crossings. y-3 4-3[over]2 knots.
(iii) As y is odd these are no fresh knots ^ with. r.k. y join 1 not