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## Henry Bushby Transcription pages

### VM533B94v4-p262.jpg

Revision as of Jun 2, 2014, 5:59:19 AM edited by JLee |
Revision as of Jun 2, 2014, 5:59:44 AM edited by JLee |
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r.k. y-2, & r.k y-1.<br> | r.k. y-2, & r.k y-1.<br> | ||

(ii) With r.k.(y-2) join 1 to all even nos.<br> | (ii) With r.k.(y-2) join 1 to all even nos.<br> | ||

− | "<u>[Oro?]</u>" up to & including 1[Sideways U] y-2. This will give<br> | + | "<u>[Oro?]</u>" up to & including 1 [Sideways U] y-2. This will give<br> |

<sup>y-3</sup>/<sub>2</sub> knots of y crossings.<br> | <sup>y-3</sup>/<sub>2</sub> knots of y crossings.<br> | ||

Then with r.k (y-10 join 1 ^<i><u>[Oro?]</u></i> to all odd<br> | Then with r.k (y-10 join 1 ^<i><u>[Oro?]</u></i> to all odd<br> | ||

− | nos. ^<i>except 5</i> up to & including 1[ | + | nos. ^<i>except 5</i> up to & including 1 [Sideways U] y. This will <br> |

give <s>y-3[over]2 of y crossings.</s> <s><u>y-3</u></s> 4-3[over]2 knots. <br> | give <s>y-3[over]2 of y crossings.</s> <s><u>y-3</u></s> 4-3[over]2 knots. <br> | ||

(iii) <s> As y is odd these are no fresh knots</s> ^<i> with. r.k. y join 1 <u>not </u> | (iii) <s> As y is odd these are no fresh knots</s> ^<i> with. r.k. y join 1 <u>not </u> |

## Revision as of Jun 2, 2014, 5:59:44 AM

I_{2} Only

(5) odd c gives c-1 knots ^{c-1}/_{2} of (c+1)^{c-1}/_{2} of (c+2)}[bracket with line above]__[Oro?]__

odd c give ~~same~~ ^*c-1 knots* for __not.__

But some will be repetitions.

(6) Required: knots with y.c. Proceed

as follows:-

__A.__ Suppose y is odd.

(i)__[Oro?]__: - y c can be derived from

r.k. y-2, & r.k y-1.

(ii) With r.k.(y-2) join 1 to all even nos.

"__[Oro?]__" up to & including 1 [Sideways U] y-2. This will give

^{y-3}/_{2} knots of y crossings.

Then with r.k (y-10 join 1 ^* [Oro?]* to all odd

nos. ^

*except 5*up to & including 1 [Sideways U] y. This will

give

__y-3__

(iii)

*with. r.k. y join 1*

__not__