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# Scripto | Revision Difference | Transcription

## Henry Bushby Transcription pages

### VM533B94v4-p262.jpg

Revision as of Jun 2, 2014, 6:11:39 AM
edited by JLee
Revision as of Jun 2, 2014, 6:34:49 AM
edited by JLee
Line 1: Line 1:
I<sub>2</sub> Only<br>
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I<sub>2</sub> Only<br>(5) odd c gives c-1 knots <sup>c-1</sup>/<sub>2</sub> of (c+1)<br><sup>c-1</sup>/<sub>2</sub> of (c+2)}[bracket with line above]<u>[Oro?]</u><br>odd c give <s>same</s> ^<i>c-1 knots</i> for <u>not.</u><br>But some will be repetitions.<br>
(5) odd c gives c-1 knots <sup>c-1</sup>/<sub>2</sub> of (c+1)<br><sup>c-1</sup>/<sub>2</sub> of (c+2)}[bracket with line above]<u>[Oro?]</u><br>
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(6) Required: knots with y.c. Proceed<br>as follows:-<br><u>A.</u> Suppose y is odd.<br>(i) <u>[Oro?]</u>: - y c can be derived from<br>r.k. y-2, & r.k y-1.<br>(ii) With r.k.(y-2) join 1 to all even nos.<br>"<u>[Oro?]</u>" up to & including 1 [Sideways U] y-2. This will give<br><sup>y-3</sup>/<sub>2</sub> knots of y crossings.<br>Then with r.k (y-1) join 1 ^<i><u>[Oro?]</u></i> to all odd<br>nos. ^<i>except 5</i> up to & including 1 [Sideways U] y. This will <br>give <s><sup>y-3</sup>/<sub>2</sub> of y crossings.</s> <s><u>y-3</u></s> <sup>4-3</sup>/<sub>2</sub> knots. <br>(iii) <s> As y is odd these are no fresh knots</s> ^<i> With. r.k. y join 1 <u>not </u> to all even nos. up </i><br><s>as yet ascented in the "not" series.</s>^<i><s>by</s> to y-1 (i.e. y) excluding 2. This gives <sup>y-3</sup>/<sub>2</sub> knots.</i><br><u>B</u>. Suppose y is even.<br><s>(i)</s> <u>[Oro?]</u>:- y , c can be derived from <br>r.k y-2 & r.k y-1.<br>(i) With r.k. (y-2) join 1 to all even nos. <u>[Oro.?]</u><br>to y-2.<br><s>as in <u>A</u>.i.</s> This gives <sup>y-2</sup>/<sub>2</sub> <s>4</s> knots.
odd c give <s>same</s> ^<i>c-1 knots</i> for <u>not.</u><br>
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But some will be repetitions.<br>
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(6) Required: knots with y.c. Proceed<br>
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as follows:-<br>
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<u>A.</u> Suppose y is odd.<br>
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(i)<u>[Oro?]</u>: - y c can be derived from<br>
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r.k. y-2, & r.k y-1.<br>
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(ii) With r.k.(y-2) join 1 to all even nos.<br>
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"<u>[Oro?]</u>" up to & including 1 [Sideways U] y-2. This will give<br>
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<sup>y-3</sup>/<sub>2</sub> knots of y crossings.<br>
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Then with r.k (y-1) join 1 ^<i><u>[Oro?]</u></i> to all odd<br>
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nos. ^<i>except 5</i> up to & including 1 [Sideways U] y. This will <br>
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give <s><sup>y-3</sup>/<sub>2</sub> of y crossings.</s> <s><u>y-3</u></s> <sup>4-3</sup>/<sub>2</sub> knots. <br>
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(iii) <s> As y is odd these are no fresh knots</s> ^<i> with. r.k. y join 1 <u>not </u> to all even nos. up <s>as yet ascented in the "not" series.</s><br>
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to y-1 (i.e. y) excluding 2. This gives <sup>y-3</sup>/<sub>2</sub> knots.<br>
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## Revision as of Jun 2, 2014, 6:34:49 AM

I2 Only
(5) odd c gives c-1 knots c-1/2 of (c+1)
c-1/2 of (c+2)}[bracket with line above][Oro?]
odd c give same ^c-1 knots for not.
But some will be repetitions.
(6) Required: knots with y.c. Proceed
as follows:-
A. Suppose y is odd.
(i) [Oro?]: - y c can be derived from
r.k. y-2, & r.k y-1.
(ii) With r.k.(y-2) join 1 to all even nos.
"[Oro?]" up to & including 1 [Sideways U] y-2. This will give
y-3/2 knots of y crossings.
Then with r.k (y-1) join 1 ^[Oro?] to all odd
nos. ^except 5 up to & including 1 [Sideways U] y. This will
give y-3/2 of y crossings. y-3 4-3/2 knots.
(iii) As y is odd these are no fresh knots ^ With. r.k. y join 1 not to all even nos. up
as yet ascented in the "not" series.^by to y-1 (i.e. y) excluding 2. This gives y-3/2 knots.
B. Suppose y is even.
(i) [Oro?]:- y , c can be derived from
r.k y-2 & r.k y-1.
(i) With r.k. (y-2) join 1 to all even nos. [Oro.?]
to y-2.
as in A.i. This gives y-2/2 4 knots.