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Henry Bushby Transcription pages

VM533B94v4-p017.jpg

Revision as of Jun 18, 2014, 9:31:12 AM, created by DPepper

17
join on to 4 & 5. Therefore join 4, 5.
Now if 10 is joined
to 9, 8 must be
joined to 7 & 2 C
are annulled. [sign for therefore]
10 must be joined
to 7 or 8. It can-
not be joined to 7 or a ring will be
formed. [sign for therefore] join 10 to 8 & 7 to 9. But
2 new C. will result. Therefore 1 cannot
be joined to 6 Q.E.D.
It appears from the foregoing that
provided a twist & a l. end are
formed, & the l. end joined to the
remaining end, the T.H. will always
be formed from S2 5b/5c.
Taitsays there are only 2 1 cord
knots of 5c, & no doubt S2 5b/5c and 5C T.H. are those knots.