Henry Bushby Transcription pages
Revision as of Jun 18, 2014, 10:06:49 AM, edited by DPepper
[The following 5 lines of text are crossed out by a bold diagonal line]
It looks as if with r. ks. When n
is even, an odd no. of bights indivisible
by n gives reversibles = none; and when
n is odd, </s>an even</s> ^ any no. of bights indivisible
by n gives reversibles. e.g. I3 7b/14c, I5 2b/8c
But try further.
I find all the r.ks up to I3 7b/14c are
reversible, & hence it may be safely inferred
that all I3 are reversible. The only knot
in I3 that coincides with plait-twists [greek cap sigma] = 3
are is I3 2b/4c. The others are different.
It is possible therefore that all in I5 are
reversible. And in I7. Also that all II3 are
reversible, & so forth. No: II3 4b/8c was not
reversible. But in I5, 2b8c, 3b12c, 4b16c, 6b24c
were all reversible, and probably it may be
safely said that all I5 are so. Further,
probably all with n odd of I are so.