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## Henry Bushby Transcription pages

### VM533B94v4-p262.jpg

## Revision as of May 29, 2014, 6:15:53 AM, edited by JLee

263

I2 only

(ii) Then with r.k (y-1) join 1 to all odd

Nos. ^*" [Fro?]" to y-1 except 5.*

__A-i.__

(iii) with r.k.y, join 1 to all even

nos ^

*"*up to & including y

__not__"*excluding 2&*com-

mencing with 1[symbol]4. This will give

y-2[over]2 knots different from B.i.

The totals thus obtained therefore

are:-

y odd:

y-3+y-3+y-3[over]2 = 3(y-3)[over]2

y even: y-2[over]2 + y-

__For example__: Required [liks?] with 6c.

__B.__(i) 6-2=4, 6-1=5.

With 4 join 1 ^

*[Oro?]*to all even nos. up to

4, [rig?] 2,4. This gives 6-2[over]2=2. They are

the Weaver & Endless chain.

(ii) With 5 join 1 ^

*to odd nos. up to 5,*

__[Fro?]__6-4[over]2 = 1. It is the Timber Hitch.

(iii) With r.k.6 join 1, ^

*to even nos.*

__not__up to 6, excluding 2. [rig?] 4,6. This gives

Total 6-2+6-4+6-2[over]2 = 18-8[over]2 = 5.

[Vertical diagram and caption in a square box:] 6c