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## Henry Bushby Transcription pages

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79

in S_{5} So in S_{6}.

Therefore it would seem that

in any S, 1 must not be joined to

M_{2n}, but this must be reduced

where necessary by subtracting 2B.

i.e. values of M_{2n} are to be taken

up to 4B - 2, & 2B subtracted from

those above 2B.

Take S_{5} 12b/48c z = 1

n = 5, b = 12, 2B = 24, B/z - 1 = 11

M_{2n} are 10, 20, 30, 40, 50,__24 24 24__

6, 16, 26

giving 6, 10, 16, 20. But this

omits 8 & 18 (p 67. B.)

In point of fact 1 joined to any

even no. in S_{5} 12b/48c gives rings.

Where z = 1, it seems obvious that

as 1 passes into every bight & emerges

as an even no, previous to emerging

as __x__, if it is joined to any even no.