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Henry Bushby Transcription pages


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in S5. So in S6.
Therefore it would seem that
in any S, 1 must not be joined to
M2n, but this must be reduced
where necessary by subtracting 2B.
i.e. values of M2n are to be taken
up to 4B - 2, & 2B subtracted from
those above 2B.
Take S5 12b/48c z=1
n=5, b=12, 2B=24, B/z-1=11
M2n are 10, 20, 30, 40, 50,
24 24 24
[horizontal line]
6, 16, 26
giving 6, 10, 16, 20. But this
omits 8 & 18 (p67. B.)
In point of fact 1 joined to any
even no. in S5 12b/48c gives rings.
Where z=1, it seems obvious that
as 1 passes into every bight & emerges
as an even no, previous to emerging
as x, if it is joined to any even no.

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