Henry Bushby Transcription pages
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Take S3. 4b/8c 2B=8
M2n=6, 12, 18, 24, 30, 36
6, 4, [10
Here we have 4 & 6 only. Yet 2
gives a ring.
[?] by n. If there is no
remainder the exclusions are 2n,
4n, 8n &c. up to 2B. If there is a
remainder it represents a certain
no of bights less than n to the left
Through Under these the line
will pass & emerge in the (nth from x - this
remainder) bight, then in the (2nth
- this remainder) bight & so on. There-
fore to the even no. in that bight it
must not be joined. i.e. to 2 (n-r)
2(2n-r) &c. or M2(n-r.) up to
2B. And if there is still a re-
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