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## Henry Bushby Transcription pages

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9.

Required: Reversibles of ~~12c~~. 16c.

[sigma] diffces are 2, 4, 6, 8 etc.

16 is divisible by 2, 4, 8 only.

Values of [sigma] are 3, 5, 9. _ 3 knots.

Therefore, except in the case of 2c, of

which there is 1 knot, given y (the

coefficient of c) there are as many

knots as there are measures equal

to 2 or multiples of 2 ^* less than y* which will

divide y, & values of [sigma] = these +1.

Example : Required, reversibles of 24.

24 is divisible by 2 _ [sigma] = 3

[symbol] 2 x 2 _ [sigma] = 5

[symbol] 3 x 2 _ [sigma] = 7

[symbol] 4 x 2 _ [sigma] = 9

[symbol] 6 x 2 _ [sigma] = 13[bracket] 5 = AND.

These knots are not necessarily on /z.

__Determination of z.__

In [sigma] = 3, z = 1 except in the case of

2c, 2 + 6 (or a multiple of 6)c, in which

case z = 2. Every 3rd knot is on 2z.

(p 10 follows) 1st = 1 ([sigma]-1)c