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Henry Bushby Transcription pages


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It is possible to represent S2 5b/5c
in long form thus:-
[Caption: Now join1, 2;
4,10; 3,5
The result
is obviously
the 5C. T.H.]
It might be thought that:-
obtained by [symbol resembling>] 1 8, 9 10, 4 6, 5 7
(turned upside down) was
a new k, but it is
clear that by untwisting
the bottom twist, a new
twist is added to the top, & the T.H. results.
Evidently 2 ^ or more unguarded twists at each
end are unstable & can be added on
to the reverse end from either until the
guard is reached. By a guard is meant
a cord passing through a bight above
the twist or below it, thus:-

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