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Henry Bushby Transcription pages


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follows: --
In the above process 8,9 is the only
bight not cut. The operation is [________?] com-
plicated that it is going rather far to
say that the one knot is or can be
derived from the other. On the other
hand the T. H. is fairly derived both
on pp 19 & 25. It would be curious
if in the case of any knot in [__________???]
whether on 1 cord or more, a single
cord T.H. with the [_______??] no. of C as
the knot could always be produced by
joining 1,2; 3,5; 4 & [alpha??]. Try this. Proved
in case of Sz [5b/5c], Sz [6b/6c].
[under first fraction "z=1", under second fraction "z=2"]

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