Log in to Scripto | Recent changes | View item | View file

## Henry Bushby Transcription pages

### VM533B94v4-p029.jpg

« previous page | next page » |

You don't have permission to transcribe this page.

## Current Page Transcription [history]

29

Join 1,2, 3,5; 2,4; in [J"S?"]2

There is still no 5 till we get to S2 [3b/3c]

& this is really a T.H. already. But

if the process is applied, result is the

reflection of the knot. (z=1)

Sz [4b/4c] (z=2) Result, Figure 8 on 1z

(a T.H.)

Sz [5b/5c], 5c T.H. (z=1) p 19.

Sz [6b/6c] (z=2): 6c T.H. (z=1)

Sz [7b/7c] (z=1): 7c T.H. (z=1)

Sz [8b/8c] (z=2): 8c T.H. (z=1)

Therefore this general rule may be

laid down: An irregular knot, the

Timber Hirch of the same no. of C. as

any knot in Sz with more than 2c, can

be obtained *on 1 cord,* [___________?] other methods by

joining 1,2; x,4; 3,5, and in the case

of Sz [3b/3c] it is merely another form of

the r.k. and in the case of Sz [4b/4c] it is