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? Nx y/N B/
1 + N yC = (y/N - 1)y/N 1 + NB/(y/N - 1)(1 + N)C
II5 -- will not go into
Try putting MN with M as 2 - a measure
of N & y for N after 1st time. Then
II5 4/2 x 2 B/4c = (4/2 x 2 - 1)4/2x2 (1 + 2 x 2)B/(4/2 x 2 - 1)(1 + 2 x2)C
= O1 5B/(O x 5)C
= O1 5B/O C which is correct.
May we therefore accept the formula
with substitution of MN for N after
the group no has been defined? M being
a factor of N?-- of y ? -- of both>
y is always a multiple of N. Therefore
factors of y are factors of N.
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