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[pencil]M qua factor of y=y/D where
D is any divisor of y
y/MN = y/yN/D = D/N = x
∴ when x = D/N then [?]
[?] D = Nx & N = D/x but II5 4b/15c
∴ where y is divisible by Nx it [should?] suffice
[Top half of page overwritten with pen]
XXM qua factor of y = y/D where D is
any divisor of y
∴ y/MN = y/yN/D = D/N = x ([?]x hypoth)
∴ x = D/N , N = D/x , D = Nx.
∴ where y is divisible by Nx it shld suffice
But II5 4b/16c is irreducible though Nx=8 & y=16
∴ it is not true that M may be any factor of y.
And II5 4b/16c also has in for x 16/2×2 where
2 is a factor of II. ∴ it is not true that it may be of N.
S7 1b/6c 2b/12c 3b/18c 4b/24c 5b/30c 6b/36c 7b/42c
II7 3b/18c = II7 18/3×2 b/18c
Here 3 is the multiple, a factor of y &
not of II
2=GCM of 3 & y. None
Required therefore II7 3b/18c
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