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Henry Bushby Transcription pages

VM533B94v4-p203.jpg

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203
(4) The reverse alternate crossing no
in any table is the alternate crossing
knot no. in the next higher table.
Thus y=3. Alternate crossing
no = No 3. Reverse = 8 - 3 + 1 = 6.
And 6 is the alternate crossing knot
no is y = 4 table.
6. I2 3B/3C first appears as No 3, y = 3.
It is also (reversed) No 6 [ditto symbol] 3 [bracket joining line above]
But also No 3 y = 5
9, y [ditto symbol] 5
12 y [ditto symbol] 5
15 y [ditto symbol] 5 [bracket joining 3 lines above]
[Caption: Every 3rd no in y = 5 (p195) considered as belonging to 52]
It is probably No 3 y = 7
So I2 5B/5C first appears as No 11 of y = 5
It is also (reversed) [ditto symbol] 22 [ditto symbol] [ditto symbol]
It is probably No 11 [ditto symbol] y = 7
[ditto symbol] 2233 [ditto symbol]
& 8 others in y = 7.

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