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## Henry Bushby Transcription pages

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## Current Page Transcription [history]

__not__

1[sideways U] to one of these numbers, and

continue, diminishing by 1 each time

until 1[sideways U] 3[overwritten in pencil with 4?], when stop. Thus, given

9c. odd. [therefore] commence with 1[sideways U] bights,

no of : =9

[Following section overwritten with vertical text: p260 ff.].

1[sideways U] bights, no of : =9

1[sideways U] [horizontal line] -1 =8

1[sideways U] [horizontal line] -2 =7

1[sideways U] [horizontal line] -3 =6

1[sideways U] [horizontal line] -4 =5

1[sideways U] [horizontal line] -5 =4~~1[sideways U] [horizontal line] -6 =3~~

These will be all the knots which need be

considered. The no. of crossings will be

found from the following table:-

[brackets enclosing 2 lines]even c 1[sideways U] bights no of, +1

odd c 1[sideways U] bights, no of.[close brackets] subtract 3c

[brackets enclosing 2 lines]even c 1[sideways U] [horizontal line] (-0)

odd c 1[sideways U] [horizontal line] -1[close brackets] c unaltered

[brackets enclosing 2 lines]even c 1[sideways U] [horizontal line] -1

odd c 1[sideways U] [horizontal line] -2[close brackets] subtract 4c

[brackets enclosing 2 lines]even c 1[sideways U] [horizontal line] -2

odd c 1[sideways U] [horizontal line] -3[close brackets] c unaltered.