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Henry Bushby Transcription pages

VM533B94v4-p250.jpg

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not
1[sideways U] to one of these numbers, and
continue, diminishing by 1 each time
until 1[sideways U] 3[overwritten in pencil with 4?], when stop. Thus, given
9c. odd. [therefore] commence with 1[sideways U] bights,
no of : =9
[Following section overwritten with vertical text: p260 ff.].
1[sideways U] bights, no of : =9
1[sideways U] [horizontal line] -1 =8
1[sideways U] [horizontal line] -2 =7
1[sideways U] [horizontal line] -3 =6
1[sideways U] [horizontal line] -4 =5
1[sideways U] [horizontal line] -5 =4
1[sideways U] [horizontal line] -6 =3
These will be all the knots which need be
considered. The no. of crossings will be
found from the following table:-
[brackets enclosing 2 lines]even c 1[sideways U] bights no of, +1
odd c 1[sideways U] bights, no of.[close brackets] subtract 3c
[brackets enclosing 2 lines]even c 1[sideways U] [horizontal line] (-0)
odd c 1[sideways U] [horizontal line] -1[close brackets] c unaltered
[brackets enclosing 2 lines]even c 1[sideways U] [horizontal line] -1
odd c 1[sideways U] [horizontal line] -2[close brackets] subtract 4c
[brackets enclosing 2 lines]even c 1[sideways U] [horizontal line] -2
odd c 1[sideways U] [horizontal line] -3[close brackets] c unaltered.

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