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Henry Bushby Transcription pages

VM533B94v4-p254.jpg

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254. Iz 8b/8c
[diagram] 1 [Sideways U] b = 1 [Sideways U] 8
c = 8, unaltered
z = 3.
[Line]
[Diagram] 1 [Sideways U] b + 1 = 1 [Sideways U] 9
c = 5 = 8 - 3
z = 2 [diagram]
[Line]
Deductions from pp 265
[Table]
Not. 1 [Sideways U] 2 1 [Sideways U] 3 1 [Sideways U] 4 1 [Sideways U] 5
13 2b/4c 4c-2c=2c 4c-1c=3c
1z+1z=2z z=z
13 3b/6c 6c-1c=5c 6c-1c=5c
3z-1z=2z 3z-1z=2z
13 4b/8c 8c-1c=9c 8c-1c=7c 8c=8c 8c=8c
1z+1z=2z 1z=1z 1z+1z=2z 1z=1z
13 5b/10c 10c-1c=9c 10c-1c=9c 10c=10c 10c+1c=11c
1z+1z=2z 1z=1z 1z+1z=2z 1z-1z
[Oro.?]
13 2/4 4c+2c=6c 4c+1c=5c
1z+1z=2z z=z
13 3/6 6c+2c=8c 6c+1c=7c
3z-1z=2z 3z-1z=2z
13 4/8 8c+2c=10c 8c+1c=9c 8c+2c=10c 8c+1c=9c
1z+1z=2z 1z=1z 1z+1z=2z 1z =1z
13 5/10

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