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(5) odd c gives c-1 knots c-1/2 of (c+1)
c-1/2 of (c+2)}[bracket with line above][Oro?]
odd c give
same ^c-1 knots for not.
But some will be repetitions.
(6) Required: knots with y.c. Proceed
A. Suppose y is odd.
(i) [Oro?]: - y c can be derived from
r.k. y-2, & r.k y-1.
(ii) With r.k.(y-2) join 1 to all even nos.
"[Oro?]" up to & including 1 [Sideways U] y-2. This will give
y-3/2 knots of y crossings.
Then with r.k (y-1) join 1 ^[Oro?] to all odd
nos. ^except 5 up to & including 1 [Sideways U] y. This will
y-3/2 of y crossings. y-3 4-3/2 knots.
As y is odd these are no fresh knots ^ With. r.k. y join 1 not to all even nos. up as yet ascented in the "not" series.^ by to y-1 (i.e. y) excluding 2. This gives y-3/2 knots.
B. Suppose y is even.
(i) [Oro?]:- y , c can be derived from
r.k y-2 & r.k y-1.
(i) With r.k. (y-2) join 1 to all even nos. [Oro.?]
as in A.i. This gives y-2/2 4 knots.
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