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Henry Bushby Transcription pages

VM533B94v4-p264.jpg

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264

(I2 only)
[underline in pencil]Next: Required i. knots of 5c.


A. (I) 5-2 = 3, 5-1 = 4
With r. k. 3c, join I ^Oro to all even nos. up
to 5-2, i.e. 2 only. The knots given are
5-3/2 = 1. viz the 5c. 2z i. k. [pencil] (There are 2 such
however)
(ii)(ii) With r. k. 4c. join1 Oro to all
odd nos. up to 4+1 = 5, viz except 5, viz:
3. This gives 5-3/2 knots = 1 knot. It is
the 5c.T.H.
(iii)With r. k. 5 join I ^not to all even
nos. up to 4 (6) excluding 2. i.e. 1 [sigma] 4.
This gives 5-3/2 knots = 1. It is an b ended
chain knot.
There are therefore 3(5-3)/2 knots = 3.
[left margin] diagram and writing bottom to top] 5c i. k. 2z not yet found.

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