Log in to Scripto | Recent changes | View item | View file

## Henry Bushby Transcription pages

### VM533B94v4-p269.jpg

« previous page | next page » |

You don't have permission to transcribe this page.

## Current Page Transcription [history]

269

__Examination of 0 _{1}__

__Oro__.

^{2b}/

_{0c}[diagram] 1 [sigma] 2

__Oro__.

gives I

_{2}

^{2b}/

_{2c}z = z

0 + z = 2c, 1z+1z = 2z.

^{2b}/

_{0c}[diagram] 1 [sigma] 3

__Oro__.

gives 0

_{1}

^{1b}/

_{0c}

0c = 0c

1z = 1z

^{3b}/

_{0c}[diagram] 1 [sigma] 2

__Oro__

gives I

_{2}

^{2b}/

_{2c}z = z

0 + z = 2c, 1z + 1z = 2z

^{3b}/

_{0c}[diagram] 1 [sigma] 3 Oro

gives 0

_{1}

^{1b}/

_{0c}

0c = 0c

1z = 1z.

^{3b}/

_{0c}[diagram] 1 [sigma] 4 Oro

gives I

_{2}

^{2b}/

_{2c}

0+2c = 2c 1z+1z = 2

_{7}

repeats 1 [sigma] 2 Oro

^{3b}/

_{0c}[diagram] 1[sigma] 5 Oro

repeats 1 [sigma] 3 Oro.

It is evident at this point that more than

2c can never be obtained.