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Henry Bushby Transcription pages

VM533B94v4-p269.jpg

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269


Examination of 01 Oro.


2b/0c [diagram] 1 [sigma] 2 Oro.
gives I2 2b/2c z = z
0 + z = 2c, 1z+1z = 2z.

2b/0c [diagram] 1 [sigma] 3 Oro.
gives 01 1b/0c
0c = 0c
1z = 1z

3b/0c [diagram] 1 [sigma] 2 Oro
gives I2 2b/2c z = z
0 + z = 2c, 1z + 1z = 2z

3b/0c [diagram] 1 [sigma] 3 Oro
gives 01 1b/0c
0c = 0c
1z = 1z.

3b/0c [diagram] 1 [sigma] 4 Oro
gives I2 2b/2c
0+2c = 2c 1z+1z = 27
repeats 1 [sigma] 2 Oro

3b/0c [diagram] 1[sigma] 5 Oro
repeats 1 [sigma] 3 Oro.

It is evident at this point that more than
2c can never be obtained.

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