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Henry Bushby Transcription pages


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[over pencil diagram] I3 5b/10c [diagram] = [diagram] = overhand
+ ring.
[over 2nd diagram] 1 [sigma] 2 not.
[lower right of 2nd diagram] 9c
10c-1c = 9c 1z =[corrected with vertical to] + 1z = 2z

[diagram] = [diagram][over diagram] 1 [sigma] 3 not.
9c. i.k. 1z.
overhand with bight
turned back
10c-1c = 9c. 1z = 1z

[diagram]=[diagram] 1[sigma] 4 not.
10c. i.k. ring
+ twisted overhand
10c = 10c, 1z+1z = 2z

[diagram] = [diagram][under each diagram] 11c [right of diagrams] 1 [sigma] 5 not.
11c, 1z.
10c+1c = 11c.
10c+1c=11c. 1z = 1z.

Evidently after this point I series knots
become highly complicated & with many c.

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