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Henry Bushby Transcription pages

VM533B94v4-p271.jpg

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I3 Format Knots (S3)


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Examination of II.3.


II3 2b/4c [diagram] [right of diagram] 1 [sigma] 2 not
gives I2 2b/2c
(4c)-2c = 2c, 1z+1z=2z

II3 2b/4c [diagram] [right of diagram] 1 [sigma] 2 Oro.
gives 5c 2zik.
[diagram] (4c) + 1c = 5c
1z+1z = 2z

II3 2b/4c [diagram] 1 [sigma] 3 not.
(4c)-4x = 0c
1z = 1z

II3 2b/4c 1[sigma] 3 Oro
[diagram] = [diagram] = I3 2b/4c
(4c) = 4c, 1z = 1z.


II3 3b/6c 1 [sigma] 2 not.
[diagram] gives 02 2b/0c (2 rings)
6c-6c = 0c
3z-1z = 2z

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