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Henry Bushby Transcription Pages

VM533B94v6_244.jpg

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244
[roman 4](sub 5) [fraction 2B/8C]
K(sub 5) [2a/8c] (sub Z = 1) = (by formula) K(sub 2) (5a/5c) = I (sub 2) (5B/5C)

[roman 4](sub 5) (3B/12C)

Reduces to
K(sub 3) (5a/10c) [checkmark symbol]
done. [checkmark symbol]
(i.e. [roman 2](sub 3) (5A/10C)

K(sub 5) (3A/12c) (sub z = 1)

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