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Henry Bushby Transcription Pages

VM533B94v6_250.jpg

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250

K(sub 6) (1a/5c
z = 1 reduces to [zero](sub 1) (6B/[zero]C)

[scratched out] IV(sub 5) (2B/10C)
[roman 5](sub 6) (2B/10C)

K(sub 6) (2a/10c)
z = 2 reduces to [roman 1](sub 2) (6B/6C)

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