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Henry Bushby Transcription Pages

VM533B94v6_267.jpg

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267
are represented by Sn bc, so in K
they are represented by Kn ac,
where a stands for arcs. (In
neither case do these expressions in-
dicate fractions.)
Thus the Torsion Knot corresponding
to S4 6b18c is K4 6a18c
[A right-facing arrow in the left margin]
(ix.[gamma]) The analogy is so complete that
the algebraical deductions made for
S in ii.p263ff, apply mutatis mutandis
to K.
[Note: The remainder of this page is highlighted by a bold vertical line in the left margin]
(x.) Whereas in S all the knots are
irreducible to knots with fewer crossings
in every series in K (except K1)
there is one Torsion Knots (perhaps^ in which a
more ?), ^ is less than n are reducible to a Torsion Knots
in the ^ a preceding series. The formula
indicating the pairs of knots is :-
p266.i.
[The following two expressions are deleted by a wavy line]
Kn (n-1) a(n-1)2 c = K (n-1) na[(n-1)2 -1]c

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