Henry Bushby Transcription Pages
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prime to one another, z = 1.
Therefore In the formula
when n, & a⁄n
C is always (n-1)2c.
by (n-1) to bring it to the form c⁄n-1>
Therefore if n & (n-1)2 c⁄(n-1) are prime
to one another, z = 1. Therefore if
n & (n-1) are so, z = 1. But these
must be so (except when n = z). Hence
z = 1. And when n = z, z also equals
The reduced knot therefore is on one cord also.
(xi) It is probable that all the other
knots in any series Kn are ir-
(xii) Except that in K the crossings
are governed by ix[alpha]. supr. (p266) &
that there is (one) reducible knot
in every series, K & S are ana-
logous in every way.
(xiii) S1 & K1, S2 & K2 are identical.
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